(b) (25,234)10 = (110001010010010)2 = (61222)8 = (6292)16
(c) (-20)10 = (1011)2 = (13)8 = (B)16 dengan one’s complement
(d) (-20)10 = (1100)2 = (14)8 = (C)16 dengan two’s complement
b) (135C)16 + (1103)16 = (245F)16
c) (110101)2 – (1011)2 = (101010)2
d) (23)4 X (31)4 = (10033)4
e) (1766)8 – (23)8 = (1743)8
f) (11101101)2 / (11101)2 = (1000)2
b) (A1EF)16 = (1010000111101111)2 = (A1EF)16
c) (11101)2 = (35)8 = (1D)16
d) (237.55)8 = (11101101. 101101)2 = (ED. 2D)16
e) (10111.1011)2 = (27.13)8 = (17.B)16
f) (CE13.A2)16 = (1100111000010011. 10100010)2 = (147023. 242)8
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